Base | Representation |
---|---|
bin | 10010111100111111100… |
… | …110101101110000101001 |
3 | 11121111211102210021120121 |
4 | 102330333212231300221 |
5 | 132314400201013301 |
6 | 2434200024323241 |
7 | 163045506033265 |
oct | 22747746556051 |
9 | 4544742707517 |
10 | 1302442204201 |
11 | 4623a9740376 |
12 | 190509313521 |
13 | 95a8706bc98 |
14 | 47077a730a5 |
15 | 23d2d5363a1 |
hex | 12f3f9adc29 |
1302442204201 has 4 divisors (see below), whose sum is σ = 1307394456192. Its totient is φ = 1297489952212.
The previous prime is 1302442204177. The next prime is 1302442204207. The reversal of 1302442204201 is 1024022442031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1302442204201 - 25 = 1302442204169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1302442204207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2476125601 + ... + 2476126126.
It is an arithmetic number, because the mean of its divisors is an integer number (326848614048).
Almost surely, 21302442204201 is an apocalyptic number.
It is an amenable number.
1302442204201 is a deficient number, since it is larger than the sum of its proper divisors (4952251991).
1302442204201 is an equidigital number, since it uses as much as digits as its factorization.
1302442204201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4952251990.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 1302442204201 its reverse (1024022442031), we get a palindrome (2326464646232).
The spelling of 1302442204201 in words is "one trillion, three hundred two billion, four hundred forty-two million, two hundred four thousand, two hundred one".
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