13024427011 has 4 divisors (see below), whose sum is σ = 13218821512. Its totient is φ = 12830032512.

The previous prime is 13024426999. The next prime is 13024427033. The reversal of 13024427011 is 11072442031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13024427011 is a prime.

It is a super-3 number, since 3×13024427011³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13024427411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97197150 + ... + 97197283.

It is an arithmetic number, because the mean of its divisors is an integer number (3304705378).

Almost surely, 2^13024427011 is an apocalyptic number.

13024427011 is a deficient number, since it is larger than the sum of its proper divisors (194394501).

13024427011 is an equidigital number, since it uses as much as digits as its factorization.

13024427011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194394500.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 13024427011 its reverse (11072442031), we get a palindrome (24096869042).

The spelling of 13024427011 in words is "thirteen billion, twenty-four million, four hundred twenty-seven thousand, eleven".