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13024442315 = 52604888463
BaseRepresentation
bin11000010000101000…
…10011011111001011
31020121200210020000102
430020110103133023
5203133224123230
65552223000015
7640520635013
oct141024233713
936550706012
1013024442315
115583a5a315
122635a3900b
1312c747c101
148b7accc43
1551367e045
hex3085137cb

13024442315 has 4 divisors (see below), whose sum is σ = 15629330784. Its totient is φ = 10419553848.

The previous prime is 13024442309. The next prime is 13024442371. The reversal of 13024442315 is 51324442031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51324442031 = 199257911769.

It is a cyclic number.

It is not a de Polignac number, because 13024442315 - 28 = 13024442059 is a prime.

It is a super-3 number, since 3×130244423153 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1302444227 + ... + 1302444236.

It is an arithmetic number, because the mean of its divisors is an integer number (3907332696).

Almost surely, 213024442315 is an apocalyptic number.

13024442315 is a deficient number, since it is larger than the sum of its proper divisors (2604888469).

13024442315 is an equidigital number, since it uses as much as digits as its factorization.

13024442315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2604888468.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 13024442315 its reverse (51324442031), we get a palindrome (64348884346).

The spelling of 13024442315 in words is "thirteen billion, twenty-four million, four hundred forty-two thousand, three hundred fifteen".

Divisors: 1 5 2604888463 13024442315