130254156141 has 4 divisors (see below), whose sum is σ = 173672208192. Its totient is φ = 86836104092.

The previous prime is 130254156139. The next prime is 130254156167. The reversal of 130254156141 is 141651452031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130254156141 - 2¹ = 130254156139 is a prime.

It is a super-3 number, since 3×130254156141³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130254156191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21709026021 + ... + 21709026026.

It is an arithmetic number, because the mean of its divisors is an integer number (43418052048).

Almost surely, 2^130254156141 is an apocalyptic number.

It is an amenable number.

130254156141 is a deficient number, since it is larger than the sum of its proper divisors (43418052051).

130254156141 is an equidigital number, since it uses as much as digits as its factorization.

130254156141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43418052050.

The product of its (nonzero) digits is 14400, while the sum is 33.

The spelling of 130254156141 in words is "one hundred thirty billion, two hundred fifty-four million, one hundred fifty-six thousand, one hundred forty-one".