Search a number
-
+
13030001132002 = 251977125343913
BaseRepresentation
bin1011110110011100100010…
…0101101100000111100010
31201010122201011220221110121
42331213020211230013202
53201440420242211002
643413522212550454
72513246401123501
oct275471045540742
951118634827417
1013030001132002
114173aa0a47268
12156537502242a
1373695435882a
14330926686838
15178e18436237
hexbd9c896c1e2

13030001132002 has 8 divisors (see below), whose sum is σ = 19545377885676. Its totient is φ = 6514875170112.

The previous prime is 13030001131963. The next prime is 13030001132021. The reversal of 13030001132002 is 20023110003031.

13030001132002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 12883426243801 + 146574888201 = 3589349^2 + 382851^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62568003 + ... + 62775910.

Almost surely, 213030001132002 is an apocalyptic number.

13030001132002 is a deficient number, since it is larger than the sum of its proper divisors (6515376753674).

13030001132002 is a wasteful number, since it uses less digits than its factorization.

13030001132002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125395892.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13030001132002 its reverse (20023110003031), we get a palindrome (33053111135033).

The spelling of 13030001132002 in words is "thirteen trillion, thirty billion, one million, one hundred thirty-two thousand, two".

Divisors: 1 2 51977 103954 125343913 250687826 6515000566001 13030001132002