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130300032013 = 136943951491
BaseRepresentation
bin111100101011001111…
…1001011010000001101
3110110022211111110011121
41321112133023100031
54113323302011023
6135505313520541
712261645666154
oct1712637132015
9413284443147
10130300032013
1150294a75678
1221305273151
13c3970b4078
14644128a59b
1535c937bd5d
hex1e567cb40d

130300032013 has 4 divisors (see below), whose sum is σ = 130301120448. Its totient is φ = 130298943580.

The previous prime is 130300032011. The next prime is 130300032047. The reversal of 130300032013 is 310230003031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 130300032013 - 21 = 130300032011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130300032011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338803 + ... + 612688.

It is an arithmetic number, because the mean of its divisors is an integer number (32575280112).

Almost surely, 2130300032013 is an apocalyptic number.

It is an amenable number.

130300032013 is a deficient number, since it is larger than the sum of its proper divisors (1088435).

130300032013 is an equidigital number, since it uses as much as digits as its factorization.

130300032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1088434.

The product of its (nonzero) digits is 162, while the sum is 16.

Adding to 130300032013 its reverse (310230003031), we get a palindrome (440530035044).

The spelling of 130300032013 in words is "one hundred thirty billion, three hundred million, thirty-two thousand, thirteen".

Divisors: 1 136943 951491 130300032013