13030041111 has 4 divisors (see below), whose sum is σ = 17373388152. Its totient is φ = 8686694072.

The previous prime is 13030041071. The next prime is 13030041131. The reversal of 13030041111 is 11114003031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13030041111 - 2⁶ = 13030041047 is a prime.

It is a super-2 number, since 2×13030041111² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13030041131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2171673516 + ... + 2171673521.

It is an arithmetic number, because the mean of its divisors is an integer number (4343347038).

Almost surely, 2^13030041111 is an apocalyptic number.

13030041111 is a deficient number, since it is larger than the sum of its proper divisors (4343347041).

13030041111 is an equidigital number, since it uses as much as digits as its factorization.

13030041111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4343347040.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13030041111 its reverse (11114003031), we get a palindrome (24144044142).

The spelling of 13030041111 in words is "thirteen billion, thirty million, forty-one thousand, one hundred eleven".