130302011013 has 4 divisors (see below), whose sum is σ = 173736014688. Its totient is φ = 86868007340.

The previous prime is 130302010991. The next prime is 130302011027. The reversal of 130302011013 is 310110203031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130302011013 - 2⁵ = 130302010981 is a prime.

It is a super-2 number, since 2×130302011013² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130302010983 and 130302011001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130302012013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21717001833 + ... + 21717001838.

It is an arithmetic number, because the mean of its divisors is an integer number (43434003672).

Almost surely, 2^130302011013 is an apocalyptic number.

It is an amenable number.

130302011013 is a deficient number, since it is larger than the sum of its proper divisors (43434003675).

130302011013 is an equidigital number, since it uses as much as digits as its factorization.

130302011013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43434003674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 130302011013 its reverse (310110203031), we get a palindrome (440412214044).

The spelling of 130302011013 in words is "one hundred thirty billion, three hundred two million, eleven thousand, thirteen".