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130305001 = 199654799
BaseRepresentation
bin1111100010001…
…00101111101001
3100002012011212011
413301010233221
5231324230001
620532515521
73141400651
oct761045751
9302164764
10130305001
1167610092
123777bba1
1320cc4568
141343d361
15b68dd51
hex7c44be9

130305001 has 4 divisors (see below), whose sum is σ = 130960000. Its totient is φ = 129650004.

The previous prime is 130304969. The next prime is 130305013. The reversal of 130305001 is 100503031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130305001 - 25 = 130304969 is a prime.

It is a super-2 number, since 2×1303050012 = 33958786571220002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130305041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327201 + ... + 327598.

It is an arithmetic number, because the mean of its divisors is an integer number (32740000).

Almost surely, 2130305001 is an apocalyptic number.

It is an amenable number.

130305001 is a deficient number, since it is larger than the sum of its proper divisors (654999).

130305001 is an equidigital number, since it uses as much as digits as its factorization.

130305001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 654998.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 130305001 is about 11415.1215937457. The cubic root of 130305001 is about 506.9755650892.

Adding to 130305001 its reverse (100503031), we get a palindrome (230808032).

The spelling of 130305001 in words is "one hundred thirty million, three hundred five thousand, one".

Divisors: 1 199 654799 130305001