13031000010011 has 4 divisors (see below), whose sum is σ = 13035226740312. Its totient is φ = 13026773279712.

The previous prime is 13031000009903. The next prime is 13031000010019. The reversal of 13031000010011 is 11001000013031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13031000010011 - 2²² = 13030995815707 is a prime.

It is a super-2 number, since 2×13031000010011² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13031000009974 and 13031000010001.

It is not an unprimeable number, because it can be changed into a prime (13031000010019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2113360526 + ... + 2113366691.

It is an arithmetic number, because the mean of its divisors is an integer number (3258806685078).

Almost surely, 2^{13031000010011} is an apocalyptic number.

13031000010011 is a deficient number, since it is larger than the sum of its proper divisors (4226730301).

13031000010011 is an equidigital number, since it uses as much as digits as its factorization.

13031000010011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4226730300.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 13031000010011 its reverse (11001000013031), we get a palindrome (24032000023042).

The spelling of 13031000010011 in words is "thirteen trillion, thirty-one billion, ten thousand, eleven".