Base | Representation |
---|---|
bin | 10010111101100110110… |
… | …100000000110000010111 |
3 | 11121120112021112211120020 |
4 | 102331212310000300113 |
5 | 132322222100020203 |
6 | 2434345203240223 |
7 | 163101014153142 |
oct | 22754664006027 |
9 | 4546467484506 |
10 | 1303100001303 |
11 | 462706a85041 |
12 | 190671679073 |
13 | 95b60422c39 |
14 | 470db183059 |
15 | 23d6b16e153 |
hex | 12f66d00c17 |
1303100001303 has 16 divisors (see below), whose sum is σ = 1793867615232. Its totient is φ = 840543912000.
The previous prime is 1303100001293. The next prime is 1303100001349. The reversal of 1303100001303 is 3031000013031.
It is not a de Polignac number, because 1303100001303 - 25 = 1303100001271 is a prime.
It is a super-2 number, since 2×13031000013032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1303100001353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 906313 + ... + 1851378.
It is an arithmetic number, because the mean of its divisors is an integer number (112116725952).
Almost surely, 21303100001303 is an apocalyptic number.
1303100001303 is a deficient number, since it is larger than the sum of its proper divisors (490767613929).
1303100001303 is a wasteful number, since it uses less digits than its factorization.
1303100001303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2762806.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 1303100001303 its reverse (3031000013031), we get a palindrome (4334100014334).
The spelling of 1303100001303 in words is "one trillion, three hundred three billion, one hundred million, one thousand, three hundred three".
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