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13031011620 = 22335118326431
BaseRepresentation
bin11000010001011010…
…10111010100100100
31020122011010222102000
430020231113110210
5203141414332440
65553015445300
7640630525344
oct141055272444
936564128360
1013031011620
1155877369a0
122638086830
1312c893c283
148b891cd24
1551402a730
hex308b57524

13031011620 has 192 divisors, whose sum is σ = 44761006080. Its totient is φ = 3120854400.

The previous prime is 13031011597. The next prime is 13031011627. The reversal of 13031011620 is 2611013031.

13031011620 is a `hidden beast` number, since 1 + 3 + 0 + 31 + 0 + 11 + 620 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13031011593 and 13031011602.

It is not an unprimeable number, because it can be changed into a prime (13031011627) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 479805 + ... + 506235.

It is an arithmetic number, because the mean of its divisors is an integer number (233130240).

Almost surely, 213031011620 is an apocalyptic number.

13031011620 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13031011620, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22380503040).

13031011620 is an abundant number, since it is smaller than the sum of its proper divisors (31729994460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13031011620 is a wasteful number, since it uses less digits than its factorization.

13031011620 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26543 (or 26535 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13031011620 its reverse (2611013031), we get a palindrome (15642024651).

It can be divided in two parts, 130 and 31011620, that added together give a triangular number (31011750 = T7875).

The spelling of 13031011620 in words is "thirteen billion, thirty-one million, eleven thousand, six hundred twenty".