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130311100320000 = 28354416621499
BaseRepresentation
bin11101101000010001101010…
…110110000100100100000000
3122002101121201122010222220220
4131220101222312010210000
5114040004113140220000
61141052032033303040
736306444354614115
oct3550215266044400
9562347648128826
10130311100320000
1138580699a22206
12127471b7a04a80
135793390034782
14242713b64690c
15100ea565111a0
hex76846ad84900

130311100320000 has 360 divisors, whose sum is σ = 443953617492000. Its totient is φ = 33902069760000.

The previous prime is 130311100319947. The next prime is 130311100320097. The reversal of 130311100320000 is 23001113031.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 16369251 + ... + 22990749.

Almost surely, 2130311100320000 is an apocalyptic number.

130311100320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130311100320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221976808746000).

130311100320000 is an abundant number, since it is smaller than the sum of its proper divisors (313642517172000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130311100320000 is an frugal number, since it uses more digits than its factorization.

130311100320000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6621579 (or 6621550 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 130311100320000 its reverse (23001113031), we get a palindrome (130334101433031).

The spelling of 130311100320000 in words is "one hundred thirty trillion, three hundred eleven billion, one hundred million, three hundred twenty thousand".