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130312113301 = 196858532279
BaseRepresentation
bin111100101011100110…
…1010000110010010101
3110110100200020020120201
41321113031100302111
54113334400111201
6135510424500501
712262153454446
oct1712715206225
9413320206521
10130312113301
11502a0877507
122130931a731
13c399754066
146442b132cd
1535ca466801
hex1e57350c95

130312113301 has 4 divisors (see below), whose sum is σ = 137170645600. Its totient is φ = 123453581004.

The previous prime is 130312113257. The next prime is 130312113319. The reversal of 130312113301 is 103311213031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130312113301 - 231 = 128164629653 is a prime.

It is a super-2 number, since 2×1303121133012 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 6858532279 = 130312113301 / (1 + 3 + 0 + 3 + 1 + 2 + 1 + 1 + 3 + 3 + 0 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130312114301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3429266121 + ... + 3429266158.

It is an arithmetic number, because the mean of its divisors is an integer number (34292661400).

Almost surely, 2130312113301 is an apocalyptic number.

It is an amenable number.

130312113301 is a deficient number, since it is larger than the sum of its proper divisors (6858532299).

130312113301 is an equidigital number, since it uses as much as digits as its factorization.

130312113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6858532298.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 130312113301 its reverse (103311213031), we get a palindrome (233623326332).

The spelling of 130312113301 in words is "one hundred thirty billion, three hundred twelve million, one hundred thirteen thousand, three hundred one".

Divisors: 1 19 6858532279 130312113301