Base | Representation |
---|---|
bin | 1011110110100001000011… |
… | …0001001101110011100011 |
3 | 1201010202211120121011021020 |
4 | 2331220100301031303203 |
5 | 3202000410300104443 |
6 | 43414242312300523 |
7 | 2513321404235631 |
oct | 275502061156343 |
9 | 51122746534236 |
10 | 13031212113123 |
11 | 4174562573306 |
12 | 15656526a1743 |
13 | 736ab81c62c9 |
14 | 3309dd434351 |
15 | 178e898e0583 |
hex | bda10c4dce3 |
13031212113123 has 16 divisors (see below), whose sum is σ = 18245862226176. Its totient is φ = 8256830044320.
The previous prime is 13031212113097. The next prime is 13031212113151. The reversal of 13031212113123 is 32131121213031.
13031212113123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13031212113123 - 214 = 13031212096739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13031212113093 and 13031212113102.
It is not an unprimeable number, because it can be changed into a prime (13031212113163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 601448233 + ... + 601469898.
It is an arithmetic number, because the mean of its divisors is an integer number (1140366389136).
Almost surely, 213031212113123 is an apocalyptic number.
13031212113123 is a deficient number, since it is larger than the sum of its proper divisors (5214650113053).
13031212113123 is a wasteful number, since it uses less digits than its factorization.
13031212113123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1202918314.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13031212113123 its reverse (32131121213031), we get a palindrome (45162333326154).
The spelling of 13031212113123 in words is "thirteen trillion, thirty-one billion, two hundred twelve million, one hundred thirteen thousand, one hundred twenty-three".
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