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130312310042 = 265156155021
BaseRepresentation
bin111100101011100111…
…0000000110100011010
3110110100200121020110102
41321113032000310122
54113334422410132
6135510433015402
712262155234155
oct1712716006432
9413320536412
10130312310042
11502a09a1302
12213093b4562
13c3997c2785
146442b64c9c
1535ca4a4c62
hex1e57380d1a

130312310042 has 4 divisors (see below), whose sum is σ = 195468465066. Its totient is φ = 65156155020.

The previous prime is 130312310041. The next prime is 130312310047. The reversal of 130312310042 is 240013213031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 101805026761 + 28507283281 = 319069^2 + 168841^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130312309996 and 130312310023.

It is not an unprimeable number, because it can be changed into a prime (130312310041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32578077509 + ... + 32578077512.

Almost surely, 2130312310042 is an apocalyptic number.

130312310042 is a deficient number, since it is larger than the sum of its proper divisors (65156155024).

130312310042 is an equidigital number, since it uses as much as digits as its factorization.

130312310042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65156155023.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 130312310042 its reverse (240013213031), we get a palindrome (370325523073).

The spelling of 130312310042 in words is "one hundred thirty billion, three hundred twelve million, three hundred ten thousand, forty-two".

Divisors: 1 2 65156155021 130312310042