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130314035 = 526062807
BaseRepresentation
bin1111100010001…
…10111100110011
3100002012122020202
413301012330303
5231330022120
620533025415
73141436205
oct761067463
9302178222
10130314035
1167616955
123778526b
1320cc86c7
1413442775
15b691875
hex7c46f33

130314035 has 4 divisors (see below), whose sum is σ = 156376848. Its totient is φ = 104251224.

The previous prime is 130314017. The next prime is 130314047. The reversal of 130314035 is 530413031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130314035 - 212 = 130309939 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130313998 and 130314016.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13031399 + ... + 13031408.

It is an arithmetic number, because the mean of its divisors is an integer number (39094212).

Almost surely, 2130314035 is an apocalyptic number.

130314035 is a deficient number, since it is larger than the sum of its proper divisors (26062813).

130314035 is an equidigital number, since it uses as much as digits as its factorization.

130314035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26062812.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 130314035 is about 11415.5172900749. The cubic root of 130314035 is about 506.9872809645.

Adding to 130314035 its reverse (530413031), we get a palindrome (660727066).

The spelling of 130314035 in words is "one hundred thirty million, three hundred fourteen thousand, thirty-five".

Divisors: 1 5 26062807 130314035