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130314144000 = 283532715009
BaseRepresentation
bin111100101011101010…
…1000000100100000000
3110110100211001102011210
41321113111000210000
54113340410102000
6135510540210120
712262206643035
oct1712725004400
9413324042153
10130314144000
11502a1a34177
1221309b39940
13c399cb5461
1464430c138c
1535ca718350
hex1e57540900

130314144000 has 288 divisors, whose sum is σ = 434522350080. Its totient is φ = 34615296000.

The previous prime is 130314143963. The next prime is 130314144083. The reversal of 130314144000 is 441413031.

It is a super-2 number, since 2×1303141440002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26013496 + ... + 26018504.

It is an arithmetic number, because the mean of its divisors is an integer number (1508758160).

Almost surely, 2130314144000 is an apocalyptic number.

130314144000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130314144000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217261175040).

130314144000 is an abundant number, since it is smaller than the sum of its proper divisors (304208206080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130314144000 is an equidigital number, since it uses as much as digits as its factorization.

130314144000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5314 (or 5290 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 130314144000 its reverse (441413031), we get a palindrome (130755557031).

The spelling of 130314144000 in words is "one hundred thirty billion, three hundred fourteen million, one hundred forty-four thousand".