Base | Representation |
---|---|
bin | 11101101000010100100110… |
… | …000011001111111111110111 |
3 | 122002101220211112002212110102 |
4 | 131220110212003033333313 |
5 | 114040032031211122403 |
6 | 1141053311431344315 |
7 | 36306615243125204 |
oct | 3550244603177767 |
9 | 562356745085412 |
10 | 130314241114103 |
11 | 38581a60907312 |
12 | 1274793382209b |
13 | 5793770943917 |
14 | 242735881ccab |
15 | 100eb8c116b88 |
hex | 7685260cfff7 |
130314241114103 has 8 divisors (see below), whose sum is σ = 130590934119360. Its totient is φ = 130037629180000.
The previous prime is 130314241114087. The next prime is 130314241114121. The reversal of 130314241114103 is 301411142413031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130314241114103 - 24 = 130314241114087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130314241114193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17049023 + ... + 23479728.
It is an arithmetic number, because the mean of its divisors is an integer number (16323866764920).
Almost surely, 2130314241114103 is an apocalyptic number.
130314241114103 is a deficient number, since it is larger than the sum of its proper divisors (276693005257).
130314241114103 is an equidigital number, since it uses as much as digits as its factorization.
130314241114103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40535577.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 130314241114103 its reverse (301411142413031), we get a palindrome (431725383527134).
The spelling of 130314241114103 in words is "one hundred thirty trillion, three hundred fourteen billion, two hundred forty-one million, one hundred fourteen thousand, one hundred three".
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