Base | Representation |
---|---|
bin | 11101101000010100110110… |
… | …110000101010000000000001 |
3 | 122002101221120001121112111200 |
4 | 131220110312300222000001 |
5 | 114040033114442440140 |
6 | 1141053355324131413 |
7 | 36306625216015353 |
oct | 3550246660520001 |
9 | 562357501545450 |
10 | 130314521452545 |
11 | 38582095081781 |
12 | 127479b1696b69 |
13 | 57937b6a49361 |
14 | 2427383b550d3 |
15 | 100eba6a40030 |
hex | 768536c2a001 |
130314521452545 has 24 divisors (see below), whose sum is σ = 225894573703656. Its totient is φ = 69496133538048.
The previous prime is 130314521452517. The next prime is 130314521452571. The reversal of 130314521452545 is 545254125413031.
130314521452545 is a `hidden beast` number, since 1 + 3 + 0 + 3 + 1 + 4 + 52 + 1 + 4 + 52 + 545 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 2728482883344 + 127586038569201 = 1651812^2 + 11295399^2 .
It is not a de Polignac number, because 130314521452545 - 27 = 130314521452417 is a prime.
It is a super-2 number, since 2×1303145214525452 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 130314521452545.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 102372282 + ... + 103637411.
It is an arithmetic number, because the mean of its divisors is an integer number (9412273904319).
Almost surely, 2130314521452545 is an apocalyptic number.
130314521452545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
130314521452545 is a deficient number, since it is larger than the sum of its proper divisors (95580052251111).
130314521452545 is a wasteful number, since it uses less digits than its factorization.
130314521452545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206023761 (or 206023758 counting only the distinct ones).
The product of its (nonzero) digits is 1440000, while the sum is 45.
Adding to 130314521452545 its reverse (545254125413031), we get a palindrome (675568646865576).
The spelling of 130314521452545 in words is "one hundred thirty trillion, three hundred fourteen billion, five hundred twenty-one million, four hundred fifty-two thousand, five hundred forty-five".
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