13032000122025 has 12 divisors (see below), whose sum is σ = 21546240201872. Its totient is φ = 6950400065040.

The previous prime is 13032000121993. The next prime is 13032000122101. The reversal of 13032000122025 is 52022100023031.

It is not a de Polignac number, because 13032000122025 - 2⁵ = 13032000121993 is a prime.

It is a super-2 number, since 2×13032000122025² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13032000121992 and 13032000122010.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 86880000739 + ... + 86880000888.

Almost surely, 2^{13032000122025} is an apocalyptic number.

13032000122025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13032000122025 is a deficient number, since it is larger than the sum of its proper divisors (8514240079847).

13032000122025 is a wasteful number, since it uses less digits than its factorization.

13032000122025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173760001640 (or 173760001635 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 13032000122025 its reverse (52022100023031), we get a palindrome (65054100145056).

The spelling of 13032000122025 in words is "thirteen trillion, thirty-two billion, one hundred twenty-two thousand, twenty-five".