Base | Representation |
---|---|
bin | 1011110110100100000001… |
… | …1001111010110010110111 |
3 | 1201010211220021102200110011 |
4 | 2331221000121322302313 |
5 | 3202004024343443221 |
6 | 43414453502041051 |
7 | 2513350250305465 |
oct | 275510031726267 |
9 | 51124807380404 |
10 | 13032011312311 |
11 | 4174932707502 |
12 | 1565836279187 |
13 | 736bb4958834 |
14 | 330a77631835 |
15 | 178ed4b5a1e1 |
hex | bda4067acb7 |
13032011312311 has 4 divisors (see below), whose sum is σ = 13082719527792. Its totient is φ = 12981303096832.
The previous prime is 13032011312219. The next prime is 13032011312323. The reversal of 13032011312311 is 11321311023031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13032011312311 - 215 = 13032011279543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13032011315311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25354107355 + ... + 25354107868.
It is an arithmetic number, because the mean of its divisors is an integer number (3270679881948).
Almost surely, 213032011312311 is an apocalyptic number.
13032011312311 is a deficient number, since it is larger than the sum of its proper divisors (50708215481).
13032011312311 is an equidigital number, since it uses as much as digits as its factorization.
13032011312311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50708215480.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13032011312311 its reverse (11321311023031), we get a palindrome (24353322335342).
The spelling of 13032011312311 in words is "thirteen trillion, thirty-two billion, eleven million, three hundred twelve thousand, three hundred eleven".
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