130320212311033 has 4 divisors (see below), whose sum is σ = 130320310333840. Its totient is φ = 130320114288228.

The previous prime is 130320212311031. The next prime is 130320212311111. The reversal of 130320212311033 is 330113212023031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130320212311033 - 2¹ = 130320212311031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130320212310989 and 130320212311007.

It is not an unprimeable number, because it can be changed into a prime (130320212311031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46989363 + ... + 49685416.

It is an arithmetic number, because the mean of its divisors is an integer number (32580077583460).

Almost surely, 2^{130320212311033} is an apocalyptic number.

It is an amenable number.

130320212311033 is a deficient number, since it is larger than the sum of its proper divisors (98022807).

130320212311033 is an equidigital number, since it uses as much as digits as its factorization.

130320212311033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98022806.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 130320212311033 its reverse (330113212023031), we get a palindrome (460433424334064).

The spelling of 130320212311033 in words is "one hundred thirty trillion, three hundred twenty billion, two hundred twelve million, three hundred eleven thousand, thirty-three".