1303204042021 has 4 divisors (see below), whose sum is σ = 1489376048032. Its totient is φ = 1117032036012.

The previous prime is 1303204042003. The next prime is 1303204042027. The reversal of 1303204042021 is 1202404023031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1303204042021 - 2⁵ = 1303204041989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1303204041983 and 1303204042001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303204042027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93086002995 + ... + 93086003008.

It is an arithmetic number, because the mean of its divisors is an integer number (372344012008).

Almost surely, 2^{1303204042021} is an apocalyptic number.

It is an amenable number.

1303204042021 is a deficient number, since it is larger than the sum of its proper divisors (186172006011).

1303204042021 is an equidigital number, since it uses as much as digits as its factorization.

1303204042021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186172006010.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1303204042021 its reverse (1202404023031), we get a palindrome (2505608065052).

The spelling of 1303204042021 in words is "one trillion, three hundred three billion, two hundred four million, forty-two thousand, twenty-one".