Base | Representation |
---|---|
bin | 1011110110100100001001… |
… | …0000101000111001000001 |
3 | 1201010211222102222211112111 |
4 | 2331221002100220321001 |
5 | 3202004110330342423 |
6 | 43414500533055321 |
7 | 2513351105655553 |
oct | 275510220507101 |
9 | 51124872884474 |
10 | 13032042434113 |
11 | 41749492337aa |
12 | 1565844787541 |
13 | 736bbb2342c1 |
14 | 330a7b8134d3 |
15 | 178ed775660d |
hex | bda42428e41 |
13032042434113 has 8 divisors (see below), whose sum is σ = 13168616894048. Its totient is φ = 12895513352064.
The previous prime is 13032042434107. The next prime is 13032042434137. The reversal of 13032042434113 is 31143424023031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13032042434113 - 213 = 13032042425921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13032040434113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10766931 + ... + 11915992.
It is an arithmetic number, because the mean of its divisors is an integer number (1646077111756).
Almost surely, 213032042434113 is an apocalyptic number.
It is an amenable number.
13032042434113 is a deficient number, since it is larger than the sum of its proper divisors (136574459935).
13032042434113 is an equidigital number, since it uses as much as digits as its factorization.
13032042434113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22688943.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13032042434113 its reverse (31143424023031), we get a palindrome (44175466457144).
The spelling of 13032042434113 in words is "thirteen trillion, thirty-two billion, forty-two million, four hundred thirty-four thousand, one hundred thirteen".
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