Base | Representation |
---|---|
bin | 1011110110100100011011… |
… | …1000111101000001100010 |
3 | 1201010212011212011020110201 |
4 | 2331221012320331001202 |
5 | 3202004240222024302 |
6 | 43414512350015414 |
7 | 2513353041135433 |
oct | 275510670750142 |
9 | 51125155136421 |
10 | 13032120111202 |
11 | 4174989068745 |
12 | 15658667a756a |
13 | 736c0136028a |
14 | 330a87c7348a |
15 | 178ede49bc87 |
hex | bda46e3d062 |
13032120111202 has 4 divisors (see below), whose sum is σ = 19548180166806. Its totient is φ = 6516060055600.
The previous prime is 13032120111181. The next prime is 13032120111211. The reversal of 13032120111202 is 20211102123031.
13032120111202 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12466343854441 + 565776256761 = 3530771^2 + 752181^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13032120111202.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3258030027799 + ... + 3258030027802.
Almost surely, 213032120111202 is an apocalyptic number.
13032120111202 is a deficient number, since it is larger than the sum of its proper divisors (6516060055604).
13032120111202 is an equidigital number, since it uses as much as digits as its factorization.
13032120111202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6516060055603.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13032120111202 its reverse (20211102123031), we get a palindrome (33243222234233).
The spelling of 13032120111202 in words is "thirteen trillion, thirty-two billion, one hundred twenty million, one hundred eleven thousand, two hundred two".
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