Base | Representation |
---|---|
bin | 1011110110100100110011… |
… | …1110011100000000010001 |
3 | 1201010212102222021111120221 |
4 | 2331221030332130000101 |
5 | 3202004442341241423 |
6 | 43414530434233041 |
7 | 2513355421030636 |
oct | 275511476340021 |
9 | 51125388244527 |
10 | 13032222212113 |
11 | 4174a30764665 |
12 | 1565894a25781 |
13 | 736c1955b110 |
14 | 330a9765018d |
15 | 178ee8418e5d |
hex | bda4cf9c011 |
13032222212113 has 16 divisors (see below), whose sum is σ = 14430797536960. Its totient is φ = 11690989142976.
The previous prime is 13032222212069. The next prime is 13032222212129. The reversal of 13032222212113 is 31121222223031.
It is not a de Polignac number, because 13032222212113 - 217 = 13032222081041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13032222212413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15357495 + ... + 16183852.
It is an arithmetic number, because the mean of its divisors is an integer number (901924846060).
Almost surely, 213032222212113 is an apocalyptic number.
13032222212113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13032222212113 is a deficient number, since it is larger than the sum of its proper divisors (1398575324847).
13032222212113 is a wasteful number, since it uses less digits than its factorization.
13032222212113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31542256.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13032222212113 its reverse (31121222223031), we get a palindrome (44153444435144).
The spelling of 13032222212113 in words is "thirteen trillion, thirty-two billion, two hundred twenty-two million, two hundred twelve thousand, one hundred thirteen".
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