130331470454303 has 4 divisors (see below), whose sum is σ = 130331692705368. Its totient is φ = 130331248203240.

The previous prime is 130331470454249. The next prime is 130331470454329. The reversal of 130331470454303 is 303454074133031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130331470454303 - 2⁸ = 130331470454047 is a prime.

It is a super-2 number, since 2×130331470454303² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130331470459303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110243576 + ... + 111419517.

It is an arithmetic number, because the mean of its divisors is an integer number (32582923176342).

Almost surely, 2^{130331470454303} is an apocalyptic number.

130331470454303 is a deficient number, since it is larger than the sum of its proper divisors (222251065).

130331470454303 is an equidigital number, since it uses as much as digits as its factorization.

130331470454303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222251064.

The product of its (nonzero) digits is 544320, while the sum is 41.

The spelling of 130331470454303 in words is "one hundred thirty trillion, three hundred thirty-one billion, four hundred seventy million, four hundred fifty-four thousand, three hundred three".