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13033212230113 = 19685958538427
BaseRepresentation
bin1011110110101000011111…
…1111000011100111100001
31201010221222222011121222021
42331222013333003213201
53202014004312330423
643415213001541441
72513422102035535
oct275520777034741
951127888147867
1013033212230113
11417539958a859
121565b104a4881
137370466b199a
14330b4cd1dbc5
151790552c795d
hexbda87fc39e1

13033212230113 has 4 divisors (see below), whose sum is σ = 13719170768560. Its totient is φ = 12347253691668.

The previous prime is 13033212230089. The next prime is 13033212230117. The reversal of 13033212230113 is 31103221233031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13033212230113 - 213 = 13033212221921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13033212230117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342979269195 + ... + 342979269232.

It is an arithmetic number, because the mean of its divisors is an integer number (3429792692140).

Almost surely, 213033212230113 is an apocalyptic number.

It is an amenable number.

13033212230113 is a deficient number, since it is larger than the sum of its proper divisors (685958538447).

13033212230113 is an equidigital number, since it uses as much as digits as its factorization.

13033212230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 685958538446.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13033212230113 its reverse (31103221233031), we get a palindrome (44136433463144).

The spelling of 13033212230113 in words is "thirteen trillion, thirty-three billion, two hundred twelve million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 19 685958538427 13033212230113