1303332120131 has 4 divisors (see below), whose sum is σ = 1303360332552. Its totient is φ = 1303303907712.

The previous prime is 1303332120119. The next prime is 1303332120133. The reversal of 1303332120131 is 1310212333031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1303332120131 - 2⁶ = 1303332120067 is a prime.

It is a super-2 number, since 2×1303332120131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1303332120097 and 1303332120106.

It is not an unprimeable number, because it can be changed into a prime (1303332120133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14036801 + ... + 14129346.

It is an arithmetic number, because the mean of its divisors is an integer number (325840083138).

Almost surely, 2^{1303332120131} is an apocalyptic number.

1303332120131 is a deficient number, since it is larger than the sum of its proper divisors (28212421).

1303332120131 is an equidigital number, since it uses as much as digits as its factorization.

1303332120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28212420.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1303332120131 its reverse (1310212333031), we get a palindrome (2613544453162).

The spelling of 1303332120131 in words is "one trillion, three hundred three billion, three hundred thirty-two million, one hundred twenty thousand, one hundred thirty-one".