Base | Representation |
---|---|
bin | 11101101000101000011011… |
… | …000101101010000111000111 |
3 | 122002110221210022201120202222 |
4 | 131220220123011222013013 |
5 | 114040404132200014310 |
6 | 1141111152233522555 |
7 | 36311300662006361 |
oct | 3550503305520707 |
9 | 562427708646688 |
10 | 130335532032455 |
11 | 3858aa96aa0402 |
12 | 1274ba95b7345b |
13 | 57957848c6969 |
14 | 24283b833dd31 |
15 | 10104d637c055 |
hex | 768a1b16a1c7 |
130335532032455 has 4 divisors (see below), whose sum is σ = 156402638438952. Its totient is φ = 104268425625960.
The previous prime is 130335532032443. The next prime is 130335532032493. The reversal of 130335532032455 is 554230235533031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130335532032455 - 216 = 130335531966919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13033553203241 + ... + 13033553203250.
It is an arithmetic number, because the mean of its divisors is an integer number (39100659609738).
Almost surely, 2130335532032455 is an apocalyptic number.
130335532032455 is a deficient number, since it is larger than the sum of its proper divisors (26067106406497).
130335532032455 is an equidigital number, since it uses as much as digits as its factorization.
130335532032455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26067106406496.
The product of its (nonzero) digits is 2430000, while the sum is 44.
Adding to 130335532032455 its reverse (554230235533031), we get a palindrome (684565767565486).
The spelling of 130335532032455 in words is "one hundred thirty trillion, three hundred thirty-five billion, five hundred thirty-two million, thirty-two thousand, four hundred fifty-five".
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