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1303400311345 = 51123698187479
BaseRepresentation
bin10010111101111000101…
…101100110101000110001
311121121022012122011111101
4102331320231212220301
5132323330434430340
62434435052044401
7163111321563466
oct22757055465061
94547265564441
101303400311345
11462850550460
12190736163701
1395baa6cbba2
1447128dd766d
1523d876dec9a
hex12f78b66a31

1303400311345 has 8 divisors (see below), whose sum is σ = 1706269498560. Its totient is φ = 947927499120.

The previous prime is 1303400311337. The next prime is 1303400311373. The reversal of 1303400311345 is 5431130043031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1303400311345 - 23 = 1303400311337 is a prime.

It is a super-2 number, since 2×13034003113452 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11849093685 + ... + 11849093794.

It is an arithmetic number, because the mean of its divisors is an integer number (213283687320).

Almost surely, 21303400311345 is an apocalyptic number.

It is an amenable number.

1303400311345 is a deficient number, since it is larger than the sum of its proper divisors (402869187215).

1303400311345 is a wasteful number, since it uses less digits than its factorization.

1303400311345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23698187495.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 1303400311345 its reverse (5431130043031), we get a palindrome (6734530354376).

The spelling of 1303400311345 in words is "one trillion, three hundred three billion, four hundred million, three hundred eleven thousand, three hundred forty-five".

Divisors: 1 5 11 55 23698187479 118490937395 260680062269 1303400311345