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130340423219 = 433031172633
BaseRepresentation
bin111100101100011100…
…1010000011000110011
3110110102122111112111012
41321120321100120303
54113414122020334
6135513315341135
712262646213606
oct1713071203063
9413378445435
10130340423219
1150305853136
12213168b17ab
13c3a25869a6
1464467a233d
1535ccba99ce
hex1e58e50633

130340423219 has 4 divisors (see below), whose sum is σ = 133371595896. Its totient is φ = 127309250544.

The previous prime is 130340423201. The next prime is 130340423221. The reversal of 130340423219 is 912324043031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130340423219 is a prime.

It is a super-3 number, since 3×1303404232193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130340423419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1515586274 + ... + 1515586359.

It is an arithmetic number, because the mean of its divisors is an integer number (33342898974).

Almost surely, 2130340423219 is an apocalyptic number.

130340423219 is a deficient number, since it is larger than the sum of its proper divisors (3031172677).

130340423219 is an equidigital number, since it uses as much as digits as its factorization.

130340423219 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3031172676.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 130340423219 in words is "one hundred thirty billion, three hundred forty million, four hundred twenty-three thousand, two hundred nineteen".

Divisors: 1 43 3031172633 130340423219