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130345212301041 = 3172555788476491
BaseRepresentation
bin11101101000110001011100…
…000100111100111011110001
3122002111212202221212011212010
4131220301130010330323301
5114041033443322113131
61141115432555353133
736312062604641643
oct3550613404747361
9562455687764763
10130345212301041
1138594104284481
1212751937a527a9
13579666829823a
142428a55c34893
1510108a112eb46
hex768c5c13cef1

130345212301041 has 8 divisors (see below), whose sum is σ = 184016770307424. Its totient is φ = 81785231247680.

The previous prime is 130345212301033. The next prime is 130345212301163. The reversal of 130345212301041 is 140103212543031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130345212301041 - 23 = 130345212301033 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130345212301021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1277894238195 + ... + 1277894238296.

It is an arithmetic number, because the mean of its divisors is an integer number (23002096288428).

Almost surely, 2130345212301041 is an apocalyptic number.

It is an amenable number.

130345212301041 is a deficient number, since it is larger than the sum of its proper divisors (53671558006383).

130345212301041 is a wasteful number, since it uses less digits than its factorization.

130345212301041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2555788476511.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 130345212301041 its reverse (140103212543031), we get a palindrome (270448424844072).

The spelling of 130345212301041 in words is "one hundred thirty trillion, three hundred forty-five billion, two hundred twelve million, three hundred one thousand, forty-one".

Divisors: 1 3 17 51 2555788476491 7667365429473 43448404100347 130345212301041