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130345351055 = 542196178969
BaseRepresentation
bin111100101100100110…
…0000011011110001111
3110110102222202220012122
41321121030003132033
54113421402213210
6135514013123155
712263036126513
oct1713114033617
9413388686178
10130345351055
1150308609527
12213184894bb
13c3a35c097a
1464472c6143
1535cd32eb55
hex1e5930378f

130345351055 has 8 divisors (see below), whose sum is σ = 156451520400. Its totient is φ = 104251548096.

The previous prime is 130345351051. The next prime is 130345351079. The reversal of 130345351055 is 550153543031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130345351055 - 22 = 130345351051 is a prime.

It is a super-2 number, since 2×1303453510552 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130345351051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3068390 + ... + 3110579.

It is an arithmetic number, because the mean of its divisors is an integer number (19556440050).

Almost surely, 2130345351055 is an apocalyptic number.

130345351055 is a deficient number, since it is larger than the sum of its proper divisors (26106169345).

130345351055 is an equidigital number, since it uses as much as digits as its factorization.

130345351055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6183193.

The product of its (nonzero) digits is 67500, while the sum is 35.

Adding to 130345351055 its reverse (550153543031), we get a palindrome (680498894086).

The spelling of 130345351055 in words is "one hundred thirty billion, three hundred forty-five million, three hundred fifty-one thousand, fifty-five".

Divisors: 1 5 4219 21095 6178969 30894845 26069070211 130345351055