Base | Representation |
---|---|
bin | 111100101100110001… |
… | …1100011110111011010 |
3 | 110110110102100221212200 |
4 | 1321121203203313122 |
5 | 4113424441404200 |
6 | 135514353151030 |
7 | 12263142402513 |
oct | 1713143436732 |
9 | 413412327780 |
10 | 130351513050 |
11 | 50311038090 |
12 | 2131a55b476 |
13 | c3a496a615 |
14 | 644804ba0a |
15 | 35cdb4a800 |
hex | 1e598e3dda |
130351513050 has 288 divisors, whose sum is σ = 408766962240. Its totient is φ = 29445120000.
The previous prime is 130351512961. The next prime is 130351513063. The reversal of 130351513050 is 50315153031.
130351513050 is a `hidden beast` number, since 1 + 3 + 0 + 351 + 5 + 1 + 305 + 0 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 5725690 + ... + 5748410.
It is an arithmetic number, because the mean of its divisors is an integer number (1419329730).
Almost surely, 2130351513050 is an apocalyptic number.
130351513050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 130351513050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (204383481120).
130351513050 is an abundant number, since it is smaller than the sum of its proper divisors (278415449190).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130351513050 is a wasteful number, since it uses less digits than its factorization.
130351513050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22830 (or 22822 counting only the distinct ones).
The product of its (nonzero) digits is 3375, while the sum is 27.
Adding to 130351513050 its reverse (50315153031), we get a palindrome (180666666081).
The spelling of 130351513050 in words is "one hundred thirty billion, three hundred fifty-one million, five hundred thirteen thousand, fifty".
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