Base | Representation |
---|---|
bin | 111100101101000100… |
… | …0111111011111101111 |
3 | 110110111002211111002122 |
4 | 1321122020333133233 |
5 | 4113434444404201 |
6 | 135515343343155 |
7 | 12263321661422 |
oct | 1713210773757 |
9 | 413432744078 |
10 | 130361325551 |
11 | 5031662a396 |
12 | 213218b1abb |
13 | c3a69c4a32 |
14 | 64494839b9 |
15 | 35ce937e1b |
hex | 1e5a23f7ef |
130361325551 has 4 divisors (see below), whose sum is σ = 130467225504. Its totient is φ = 130255425600.
The previous prime is 130361325529. The next prime is 130361325599. The reversal of 130361325551 is 155523163031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130361325551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130361324551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52948130 + ... + 52950591.
It is an arithmetic number, because the mean of its divisors is an integer number (32616806376).
Almost surely, 2130361325551 is an apocalyptic number.
130361325551 is a deficient number, since it is larger than the sum of its proper divisors (105899953).
130361325551 is a wasteful number, since it uses less digits than its factorization.
130361325551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105899952.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 130361325551 its reverse (155523163031), we get a palindrome (285884488582).
The spelling of 130361325551 in words is "one hundred thirty billion, three hundred sixty-one million, three hundred twenty-five thousand, five hundred fifty-one".
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