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130370012655 = 358691334177
BaseRepresentation
bin111100101101010101…
…0001000010111101111
3110110111201011211120020
41321122222020113233
54113444210401110
6135520253453223
712263455552311
oct1713252102757
9413451154506
10130370012655
1150320523113
12213247a1213
13c3a8746b2c
14644a6a57b1
1535d05a1d70
hex1e5aa885ef

130370012655 has 8 divisors (see below), whose sum is σ = 208592020272. Its totient is φ = 69530673408.

The previous prime is 130370012639. The next prime is 130370012677. The reversal of 130370012655 is 556210073031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130370012655 - 24 = 130370012639 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4345667074 + ... + 4345667103.

It is an arithmetic number, because the mean of its divisors is an integer number (26074002534).

Almost surely, 2130370012655 is an apocalyptic number.

130370012655 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130370012655 is a deficient number, since it is larger than the sum of its proper divisors (78222007617).

130370012655 is an equidigital number, since it uses as much as digits as its factorization.

130370012655 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8691334185.

The product of its (nonzero) digits is 18900, while the sum is 33.

Adding to 130370012655 its reverse (556210073031), we get a palindrome (686580085686).

The spelling of 130370012655 in words is "one hundred thirty billion, three hundred seventy million, twelve thousand, six hundred fifty-five".

Divisors: 1 3 5 15 8691334177 26074002531 43456670885 130370012655