Search a number
-
+
13039430042 = 26519715021
BaseRepresentation
bin11000010010011010…
…11110100110011010
31020122201222200022102
430021031132212122
5203201043230132
65553520123402
7641062220012
oct141115364632
936581880272
1013039430042
115591466871
12263aa66562
1312ca5c8ca2
148b9ab0c42
15514b3ec62
hex30935e99a

13039430042 has 4 divisors (see below), whose sum is σ = 19559145066. Its totient is φ = 6519715020.

The previous prime is 13039429987. The next prime is 13039430057. The reversal of 13039430042 is 24003493031.

13039430042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11560335361 + 1479094681 = 107519^2 + 38459^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13039429987 and 13039430014.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3259857509 + ... + 3259857512.

Almost surely, 213039430042 is an apocalyptic number.

13039430042 is a deficient number, since it is larger than the sum of its proper divisors (6519715024).

13039430042 is an equidigital number, since it uses as much as digits as its factorization.

13039430042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6519715023.

The product of its (nonzero) digits is 7776, while the sum is 29.

The spelling of 13039430042 in words is "thirteen billion, thirty-nine million, four hundred thirty thousand, forty-two".

Divisors: 1 2 6519715021 13039430042