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130399121611908 = 2232611031634637639
BaseRepresentation
bin11101101001100011101001…
…010100101001110010000100
3122002201000220222201220211100
4131221203221110221302010
5114042424400113040113
61141200310211140100
736316011536345322
oct3551435124516204
9562630828656740
10130399121611908
1138604a58719656
1212760281ba4630
13579b779c25b56
14242b4cb82cd12
151011ea8cd3d73
hex7698e9529c84

130399121611908 has 288 divisors, whose sum is σ = 341131330641920. Its totient is φ = 41982598183680.

The previous prime is 130399121611873. The next prime is 130399121611921. The reversal of 130399121611908 is 809116121993031.

130399121611908 is a `hidden beast` number, since 1 + 3 + 0 + 3 + 9 + 9 + 12 + 1 + 611 + 9 + 0 + 8 = 666.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 17070178353 + ... + 17070185991.

Almost surely, 2130399121611908 is an apocalyptic number.

130399121611908 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130399121611908, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170565665320960).

130399121611908 is an abundant number, since it is smaller than the sum of its proper divisors (210732209030012).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130399121611908 is a wasteful number, since it uses less digits than its factorization.

130399121611908 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8439 (or 8434 counting only the distinct ones).

The product of its (nonzero) digits is 629856, while the sum is 54.

The spelling of 130399121611908 in words is "one hundred thirty trillion, three hundred ninety-nine billion, one hundred twenty-one million, six hundred eleven thousand, nine hundred eight".