1304000122431 has 8 divisors (see below), whose sum is σ = 1814261040000. Its totient is φ = 831536309912.

The previous prime is 1304000122423. The next prime is 1304000122459. The reversal of 1304000122431 is 1342210004031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1304000122431 - 2³ = 1304000122423 is a prime.

It is a super-2 number, since 2×1304000122431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1304000122398 and 1304000122407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304000122421) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9449276181 + ... + 9449276318.

It is an arithmetic number, because the mean of its divisors is an integer number (226782630000).

Almost surely, 2^{1304000122431} is an apocalyptic number.

1304000122431 is a deficient number, since it is larger than the sum of its proper divisors (510260917569).

1304000122431 is a wasteful number, since it uses less digits than its factorization.

1304000122431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18898552525.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1304000122431 its reverse (1342210004031), we get a palindrome (2646210126462).

The spelling of 1304000122431 in words is "one trillion, three hundred four billion, one hundred twenty-two thousand, four hundred thirty-one".