1304000443223 has 4 divisors (see below), whose sum is σ = 1312752124200. Its totient is φ = 1295248762248.

The previous prime is 1304000443153. The next prime is 1304000443231. The reversal of 1304000443223 is 3223440004031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304000443223 - 2⁸ = 1304000442967 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1304000443192 and 1304000443201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304000443253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4375840265 + ... + 4375840562.

It is an arithmetic number, because the mean of its divisors is an integer number (328188031050).

Almost surely, 2^{1304000443223} is an apocalyptic number.

1304000443223 is a deficient number, since it is larger than the sum of its proper divisors (8751680977).

1304000443223 is an equidigital number, since it uses as much as digits as its factorization.

1304000443223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8751680976.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 1304000443223 its reverse (3223440004031), we get a palindrome (4527440447254).

The spelling of 1304000443223 in words is "one trillion, three hundred four billion, four hundred forty-three thousand, two hundred twenty-three".