Base | Representation |
---|---|
bin | 10010111110011100101… |
… | …001100100001010011101 |
3 | 11121122212020010201201022 |
4 | 102332130221210022131 |
5 | 132331044311414123 |
6 | 2435014550453525 |
7 | 163132262410040 |
oct | 22763451441235 |
9 | 4548766121638 |
10 | 1304003232413 |
11 | 46302a913a32 |
12 | 1908840642a5 |
13 | 95c755ab20b |
14 | 47185100c57 |
15 | 23dc05d81c8 |
hex | 12f9ca6429d |
1304003232413 has 8 divisors (see below), whose sum is σ = 1490296319232. Its totient is φ = 1117711873296.
The previous prime is 1304003232409. The next prime is 1304003232419. The reversal of 1304003232413 is 3142323004031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1304003232413 - 22 = 1304003232409 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304003232419) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2684156 + ... + 3132522.
It is an arithmetic number, because the mean of its divisors is an integer number (186287039904).
Almost surely, 21304003232413 is an apocalyptic number.
It is an amenable number.
1304003232413 is a deficient number, since it is larger than the sum of its proper divisors (186293086819).
1304003232413 is an equidigital number, since it uses as much as digits as its factorization.
1304003232413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 863851.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1304003232413 its reverse (3142323004031), we get a palindrome (4446326236444).
The spelling of 1304003232413 in words is "one trillion, three hundred four billion, three million, two hundred thirty-two thousand, four hundred thirteen".
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