Base | Representation |
---|---|
bin | 11101101001100101100000… |
… | …100100110101000010010011 |
3 | 122002201020002102110111012020 |
4 | 131221211200210311002103 |
5 | 114042442444304403021 |
6 | 1141201240521502523 |
7 | 36316112242304634 |
oct | 3551454044650223 |
9 | 562636072414166 |
10 | 130401122341011 |
11 | 38605895013a85 |
12 | 12760740041a43 |
13 | 579ba08597022 |
14 | 242b63b43788b |
15 | 101207478c7c6 |
hex | 769960935093 |
130401122341011 has 16 divisors (see below), whose sum is σ = 175828654853280. Its totient is φ = 85953912549120.
The previous prime is 130401122341003. The next prime is 130401122341013. The reversal of 130401122341011 is 110143221104031.
It is not a de Polignac number, because 130401122341011 - 23 = 130401122341003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130401122341013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2798080 + ... + 16389981.
It is an arithmetic number, because the mean of its divisors is an integer number (10989290928330).
Almost surely, 2130401122341011 is an apocalyptic number.
130401122341011 is a deficient number, since it is larger than the sum of its proper divisors (45427532512269).
130401122341011 is a wasteful number, since it uses less digits than its factorization.
130401122341011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19213606.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 130401122341011 its reverse (110143221104031), we get a palindrome (240544343445042).
The spelling of 130401122341011 in words is "one hundred thirty trillion, four hundred one billion, one hundred twenty-two million, three hundred forty-one thousand, eleven".
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