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130401222023 = 1731247440649
BaseRepresentation
bin111100101110010000…
…1001011110110000111
3110110120212220102202202
41321130201023312013
54114030203101043
6135523330425115
712264315045602
oct1713441136607
9413525812682
10130401222023
11503370aa186
122133313219b
13c3b2053407
1464508ab339
1535d31b91b8
hex1e5c84bd87

130401222023 has 8 divisors (see below), whose sum is σ = 142525814400. Its totient is φ = 118771511040.

The previous prime is 130401221917. The next prime is 130401222043. The reversal of 130401222023 is 320222104031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130401222023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130401221986 and 130401222004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130401222043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123719798 + ... + 123720851.

It is an arithmetic number, because the mean of its divisors is an integer number (17815726800).

Almost surely, 2130401222023 is an apocalyptic number.

130401222023 is a deficient number, since it is larger than the sum of its proper divisors (12124592377).

130401222023 is a wasteful number, since it uses less digits than its factorization.

130401222023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247440697.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 130401222023 its reverse (320222104031), we get a palindrome (450623326054).

The spelling of 130401222023 in words is "one hundred thirty billion, four hundred one million, two hundred twenty-two thousand, twenty-three".

Divisors: 1 17 31 527 247440649 4206491033 7670660119 130401222023