Search a number
-
+
13040211351 = 34346737117
BaseRepresentation
bin11000010010100000…
…11101010110010111
31020122210110101001210
430021100131112113
5203201243230401
65553544552503
7641101652616
oct141120352627
936583411053
1013040211351
11559194a882
12263b182733
1312ca8107bb
148b9c3587d
15514c464d6
hex30941d597

13040211351 has 4 divisors (see below), whose sum is σ = 17386948472. Its totient is φ = 8693474232.

The previous prime is 13040211343. The next prime is 13040211361. The reversal of 13040211351 is 15311204031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13040211351 - 23 = 13040211343 is a prime.

It is a super-2 number, since 2×130402113512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040211341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173368556 + ... + 2173368561.

It is an arithmetic number, because the mean of its divisors is an integer number (4346737118).

Almost surely, 213040211351 is an apocalyptic number.

13040211351 is a deficient number, since it is larger than the sum of its proper divisors (4346737121).

13040211351 is an equidigital number, since it uses as much as digits as its factorization.

13040211351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4346737120.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 13040211351 its reverse (15311204031), we get a palindrome (28351415382).

The spelling of 13040211351 in words is "thirteen billion, forty million, two hundred eleven thousand, three hundred fifty-one".

Divisors: 1 3 4346737117 13040211351