13040221253 has 4 divisors (see below), whose sum is σ = 13040543328. Its totient is φ = 13039899180.

The previous prime is 13040221193. The next prime is 13040221267. The reversal of 13040221253 is 35212204031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13040221253 - 2¹⁰ = 13040220229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040221273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89801 + ... + 184782.

It is an arithmetic number, because the mean of its divisors is an integer number (3260135832).

Almost surely, 2^13040221253 is an apocalyptic number.

It is an amenable number.

13040221253 is a deficient number, since it is larger than the sum of its proper divisors (322075).

13040221253 is an equidigital number, since it uses as much as digits as its factorization.

13040221253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 322074.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 13040221253 its reverse (35212204031), we get a palindrome (48252425284).

The spelling of 13040221253 in words is "thirteen billion, forty million, two hundred twenty-one thousand, two hundred fifty-three".