Base | Representation |
---|---|
bin | 11000010010100001… |
… | …00010111010000010 |
3 | 1020122210111112021212 |
4 | 30021100202322002 |
5 | 203201244442424 |
6 | 5553545250122 |
7 | 641102106155 |
oct | 141120427202 |
9 | 36583445255 |
10 | 13040234114 |
11 | 5591965996 |
12 | 263b193942 |
13 | 12ca81ac7b |
14 | 8b9c3dc9c |
15 | 514c4d10e |
hex | 309422e82 |
13040234114 has 4 divisors (see below), whose sum is σ = 19560351174. Its totient is φ = 6520117056.
The previous prime is 13040234113. The next prime is 13040234153. The reversal of 13040234114 is 41143204031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11007576889 + 2032657225 = 104917^2 + 45085^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13040234114.
It is not an unprimeable number, because it can be changed into a prime (13040234113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3260058527 + ... + 3260058530.
Almost surely, 213040234114 is an apocalyptic number.
13040234114 is a deficient number, since it is larger than the sum of its proper divisors (6520117060).
13040234114 is an equidigital number, since it uses as much as digits as its factorization.
13040234114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6520117059.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13040234114 its reverse (41143204031), we get a palindrome (54183438145).
The spelling of 13040234114 in words is "thirteen billion, forty million, two hundred thirty-four thousand, one hundred fourteen".
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