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130402564153 = 4316399718661
BaseRepresentation
bin111100101110010011…
…0010011100000111001
3110110120222102121211021
41321130212103200321
54114031024023103
6135523415302441
712264332335531
oct1713446234071
9413528377737
10130402564153
1150337936584
122133367aa21
13c3b2403284
146450b3a4c1
1535d3381bbd
hex1e5c993839

130402564153 has 16 divisors (see below), whose sum is σ = 134395662016. Its totient is φ = 126454789440.

The previous prime is 130402564129. The next prime is 130402564157. The reversal of 130402564153 is 351465204031.

It is a cyclic number.

It is not a de Polignac number, because 130402564153 - 217 = 130402433081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130402564157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6978643 + ... + 6997303.

It is an arithmetic number, because the mean of its divisors is an integer number (8399728876).

Almost surely, 2130402564153 is an apocalyptic number.

It is an amenable number.

130402564153 is a deficient number, since it is larger than the sum of its proper divisors (3993097863).

130402564153 is a wasteful number, since it uses less digits than its factorization.

130402564153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19864.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 130402564153 its reverse (351465204031), we get a palindrome (481867768184).

The spelling of 130402564153 in words is "one hundred thirty billion, four hundred two million, five hundred sixty-four thousand, one hundred fifty-three".

Divisors: 1 43 163 997 7009 18661 42871 162511 802423 3041743 6987973 18605017 130794949 800015731 3032617771 130402564153