13040317 has 4 divisors (see below), whose sum is σ = 13392796. Its totient is φ = 12687840.

The previous prime is 13040297. The next prime is 13040323. The reversal of 13040317 is 71304031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 71304031 = 281 ⋅253751.

It can be written as a sum of positive squares in 2 ways, for example, as 4866436 + 8173881 = 2206^2 + 2859^2 .

It is a cyclic number.

It is not a de Polignac number, because 13040317 - 2⁷ = 13040189 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13040294 and 13040303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176184 + ... + 176257.

It is an arithmetic number, because the mean of its divisors is an integer number (3348199).

Almost surely, 2^13040317 is an apocalyptic number.

It is an amenable number.

13040317 is a deficient number, since it is larger than the sum of its proper divisors (352479).

13040317 is an equidigital number, since it uses as much as digits as its factorization.

13040317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 352478.

The product of its (nonzero) digits is 252, while the sum is 19.

The square root of 13040317 is about 3611.1379093023. The cubic root of 13040317 is about 235.3762916671.

Adding to 13040317 its reverse (71304031), we get a palindrome (84344348).

The spelling of 13040317 in words is "thirteen million, forty thousand, three hundred seventeen".